m^2-m-99=-6

Solution for m^2-m-99=-6 equation:

m^2-m-99=-6

We move all terms to the left:

m^2-m-99-(-6)=0

We add all the numbers together, and all the variables

m^2-1m-93=0

a = 1; b = -1; c = -93;
Δ = b2-4ac
Δ = -12-4·1·(-93)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{373}}{2*1}=\frac{1-\sqrt{373}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{373}}{2*1}=\frac{1+\sqrt{373}}{2}
$